`angleABC =90^@` and BM is a median `AB = 8 cm` and `BC = 6 cm`. Then, length BM is equal to

In triangle ABC , AB = 6 cm, AC = 8 cm, and BC = 9 cm. The length of median AD is:

In triangle ABC, AB = 6 cm, AC = 8 cm, and BC = 9 cm . The length of median AD is :

In triangle ABC , AB = 6 cm, AC = 8 cm, and BC = 9 cm. The length of median AD is : triangle ABC में, AB = 6 सेमी, AC = 8 सेमी, और BC = 9 सेमी। माध्यिका AD की लम्बाई क्या होगी :

DeltaABC is an isosceles triangle with AB=AC=13cm . AD is the median on BC from A such that AD=12cm . The length of BC is equal to :

In triangle ABC , angle C = 90 , AC = 6 cm, BC = 8 cm. then find the length of the median through C.

In angleABC, angleABC =90^@ , AB = 5 cm, BC = 12 cm. Find the length of the circumradius of triangleABC .

In DeltaABC, angleABC = 90^@ , AD = DC, AB = 12cm and BC = 6.5 cm. Find the area of DeltaADB .

In DeltaABC, angleABC = 90^@ , AD = DC, AB = 12cm and BC = 6.5 cm. Find the area of DeltaADB .