if `axxb = bxxc != 0` with a `!= -c` then show that a+c = kb, where k is scalar.

If vec axxvec b=vec b xxvec c != vec 0 , then show that vec a+vec c= k vec b where k is a scalar.

If vec a xxvec b=vec b xxvec c!=0, then show that vec a+vec c=mvec b, where m is any scalar.

If vec axx vec b= vec bxx vec c!=0 , then show that vec a+ vec c=m vec b , where m is any scalar.

If vec a xxvec b=vec b xxvec c!=0, then show that vec a+vec c=mvec b, where m is any scalar.

If bar(a) xx bar(b) = bar(b) xx bar(c ) != 0 , then show that bar(a) + bar(c ) = bar(p)bar(b) , where p is some scalar.

If vec a xx vec b= vec b xx vec c != vec 0 then which one is true where k is a suitable scalar?

If axxb=bxxc ne0 , then the correct statement is

If axxb=bxxc ne0 , then the correct statement is

If a'=(bxxc)/(["a b c"]),b'=(cxxa)/(["a b c"]),c'=(axxb)/(["a b c"]) then show that axxa'+bxxb'+cxxc'=0 , where a,b and c are non-coplanar.