What fraction of the volume of a vessel must liquid ether occupy at room temperature in order to pass into crictical state when critical temperature is reached ? Ether has `T_(cr) = 467 K, p_(cr) = 35.5 atm p M = 74 g//mol`.

Find the specific volume of benzence (C_6 H_6) in critical state if its critical temperature T_(cr) = 562 K and critical pressure p_(cr) = 47 atm .

Calculate the Van der Waals constant for carbon dioxide it its critical temperature T_(cr) = 304 K and critical pressure p_(cr) = 73 atm .

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) {:("Gases",A,B,C,D,),(P_(c) (atm),2.2,14,35,45,),(T_(c) (K),5.1,33,127,140,):} Which of the above gases cannot be liquefied at 100 K and 50 atm ?

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, wll be