[364" - "],[" (c) "2y^(2)=x^(3)" और "y^(2)=32x],[" (d) "y=x^(2)" 3ir "y=x^(3)]

Divide 14x^(3)y^(2)+8x^(2)y^(3)-32x^(2)y^(5) by -2xy^(2)

{:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (a) x^(2) + xy + y^(2)) , (9x^(2) - 16y^(2) ,, (b) 2) , ((x^(3) - y^(3))/(x-y) ,, (c) (9x + 16y) (9x - 16y)) , ("The degree of " (x + 2) (x+3) ,, (d) x^(2) - y^(2)) , (,, (e) 1) , (,, (f) (3x + 4y) (3x - 4y)):}

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

Find the angle between the curves 2y^(2)=x^(3) and y^(2)=32x

(x+y)^(3)-(x-y)^(3) can be factorized as 2y(3x^(2)+y^(2)) (b) 2x(3x^(2)+y^(2))2y(3y^(2)+x^(2)) (d) 2x(x^(2)+3y^(2))

Equation of the parabola with focus (0,-3) and the directrix y=3 is: (a) x^(2)=-12y (b) x^(2)=12y (c) x^(2)=3y (d) x^(2)=-3y

Solve for (x - 1)^(2) and (y + 3)^(2) , 2x^(2) - 5y^(2) - x - 27y - 26 = 3(x + y + 5) and 4x^(2) - 3y^(2) - 2xy + 2x - 32y - 16 = (x - y + 4)^(2) .

The solution of the differential equation (dy)/(dx)+(x(x^(2)+3y^(2)))/(y(y^(2)+3x^(2)))=0 is (a) x^(4)+y^(4)+x^(2)y^(2)=c (b) x^(4)+y^(4)+3x^(2)y^(2)=c (c) x^(4)+y^(4)+6x^(2)y^(2)=c (d) x^(4)+y^(4)+9x^(2)y^(2)=c