The position of a particle moving along x-axis is given by `x = 10t - 2t^(2)`. Then the time (t) at which it will momentily come to rest is

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

The position of a particle moving along x-axis varies eith time t as x=4t-t^(2)+1 . Find the time interval(s) during which the particle is moving along positive x-direction.

The position of a particle moving along x-axis varies eith time t as x=4t-t^(2)+1 . Find the time interval(s) during which the particle is moving along positive x-direction.

The position of a particle moving along x-axis varies eith time t as x=4t-t^(2)+1 . Find the time interval(s) during which the particle is moving along positive x-direction.