In a binomial distribution, if the mean is 8 and the variance is 6, then the number of trials is

In a binomial distribution, mean is 5 and the variance is 4 . The number of trials is

In a binomial distribution, mean is 5 and the variance is 4 . The number of trials is

Find the binomial distribution whose: mean is 9 and variance is 6.

If in a binomial distribution mean is 5 and variance is 4, write the number of trials.

Determine a binomial distribution whose mean is 9 and variance is 6.

In a binomial distribution mean is 4 and variance is 3, then find out number of observations.

For a binomial distribution, if mean is 8 and variance is 6, then the probability of atleast 1 success is.

If the difference between mean and variance of a binomial distribution is 2 and the mean of X is 6, then the number of trials is

If mean of a binomial distribution is 3 and its variance is 3/2 , then number of trials is :

Determine the binomial distribution whose mean is 9 and variance is 6.