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f(x)={(x^3+x^2-16 x+20)/((x-2)^2), x!=2k...

`f(x)={(x^3+x^2-16 x+20)/((x-2)^2), x!=2k ,k , x=2` . Find the value of k, so that the following function is continuous at x=2.

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The correct Answer is:
`k= 7`
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