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Find the particular solution of the differential equation. `(dy)/(dx)+ycotx=4x\ \ cos e c\ x ,\ (x!=0),\ ` given that `y=0` when `x=pi/2dot`

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Knowledge Check

  • The solution of the differential equation (dy)/(dx)+y/x=x^2 is :

    A
    `x+y=x^2/2+c`
    B
    `x-y=1/3x^3+c`
    C
    `xy=1/4x^4+c`
    D
    `y-x=1/4x^4+c`
  • Solution of the differential equation dy/dx +y/x = sin x is

    A
    x( y+ cos x) = sin x + c
    B
    x(y- cos x) = sin x + c
    C
    xy cos x = sin x + c
    D
    x(y+cos x) = cos x + c
  • The general solution of the differential equation (dy)/(dx)+y/x=3x is

    A
    `y=x - c/x`
    B
    `y= x+c/x`
    C
    `y= x^(2)- c/x`
    D
    `y = x^(2)+ c/x`
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    Solution of the differential equation (dx)/(x)+(dy)/(y)=0 is

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