In Young's double slit experiment two coherent sources of intensity ratio of `64 :1`, produce interference fringes. Calculate the ratio of maximum and minimum intensities.
Data : `I_(1) : I_(2) :: 64 : 1`, `(I_(max))/(I_(min))=?`

Explanation

`(I_(1))/(I_(2))=(a_(1)^(2))/(a_(2)^(2))=(64)/(1)`
`:.(a_(1))/(a_(2))=(8)/(1)` or `a_(1)=8a_(2)`
`(I_(max))/(I_(min))=((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=((8a_(2)+a_(2))^(2))/((8a_(2)-a_(2))^(2))`
`=((9a_(2))^(2))/((7a_(2))^(2))=(81)/(49)`
`:.I_(max) : I_(min) : : 81 : 49`