Home
Class 11
CHEMISTRY
Gas A taken in a closed rigid container ...

Gas A taken in a closed rigid container is allowed to decompose partially according to the reaction
`A(g)rarr2B(g)+3C(g)`
The gaseous mixture formed effuses 1.5 times faster than a gas having molecular weight 105 under similar conditions. Find the mole fraction of C in the gaseous mixture formed
Given : Mol. wt. of `A = 140`
Mol. wt. of `B = 64 `
Mol. wt. of `C = 4`
Write your answer by multiplying with 10.

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the molarity and mole fraction of the solute in aqueous solution containing 3.0 g of urea per 250gm of water (Mol. Wt. of urea = 60)

A 5% solution of sugarcane ( mol. wt. 342 ) is isotonic with 1% solution of X under similar conditions. The molecular mass of X is :

A gaseous mixture contain four gases A, B, C and D. The mole fraction of "B" is 0.5. The mole fraction of "A" is

If one mole of a gas A (mol.wt-40) occupies a volume of 201itres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas B (mol.wt=80) is

Mixture of 1 mole of each CH_(4) and C_(2)H_(6) absorb 5 mole of Cl_(2) to form C Cl_(4) and C_(2)Cl_(6) . Then average molecular wt. of the gaseous mixture is

Mixture of 1 mole of each CH_(4) and C_(2)H_(6) absorb 5 mole of Cl_(2) to form C Cl_(4) and C_(2)Cl_(6) . Then average molecular wt. of the gaseous mixture is

A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressure of A and B are 3.0 and 1.0 atm respectively and if C has a mol/wt. of 2.0. what is the weight of C in g present in the mixture ?