A bullet of mass A and velocity B is fired into a wooden block of mass C. If the bullet geta embedded in the wooden block.then velocity of wooden block after collision

A bullet is fired into a wooden block. If the bullet gets embedded in wooden block, then

A bullet gets embedded in a wooden block. Where does its KE go?

A bullet of mass a and velocity b is fired into a large block of mass c. the final velocity of the system is

A bullet of mass 'x' moves with a velocity y , hits a wooden block of mass z at rest and gets embedded in it. After collision, the wooden block and bullet moves with a velocity

A bullet of mass x moves with a velocity y, hits a wooden block of mass z, at rest and gets embedded in it. After collision if the wooden block with bullet in it moves the velocity is

A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If the block rises to a height h , the initial velocity of the block will be (

A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If the block rises to a height h , the initial velocity of the block will be ?

A bullet of mass m, moving with a velocity u hits a wooden block of mass M and gets embedded. Assuming that the wooden block can move freely, show that, the loss of kinetic energy =1/2 (mM)/(m+M) u^2 .