[" In the figure,"/_ABD=3/_DAB" and "/_BDC=],[96^(@)." Find "/_ABD.]

In the figure,if /_ABD=3/_DAB and /_BDC=96^(@). Find /_ABD

In the figure, angle ABD = 3 angle DAB and angle BDC = 96^(@). Find angle ABD

In Figure,if ABDE,/_BAC=35^(0) and /_CDE=53^(0), find /_DCE.

In Figure,/_ABC=69^(@),/_ACB=31^(0), find /_BDC

In the above figure, /_ ABD =20^(@), /_ BDC =110^(@) and /_ DCA =30^(@) . What is the value of /_ BAC ?

In the diagram given below,/_ABD=/_CDB=/_PQD=90^(@). If AB:CD=3:1, the ratio of CD:PQ is

In the given figure,/_ABD=/_GFD.CE bisects BF.Prove that /_C=/_E

The diagonals of a parallelogram ABCD intersect at O. If /_DBC=30^(@) and /_BDC=60^(@), then /_DAB is

BC is the diameter of a circle.Points A and D are situated on the circumference of the semi circle /_ABD=35^(@) and /_BCD=60^(@),/_ADB equals to:

In Figure,AB=AC and DB=DC, find the ratio /_ABD:/_ACD