Home
Class 11
CHEMISTRY
[" 476."1" molal aqueous solution of an ...

[" 476."1" molal aqueous solution of an electrolyte "X_(3)Y_(2)" is "25%" ionised.The boiling point of the solution is "],[(K_(b,H_(2)O)=0.52Kkg/mol)],[[" (a) "375.5K," (b) "374.04K," (c) "377.12K," (d) "373.25K]]

Promotional Banner

Similar Questions

Explore conceptually related problems

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionised . The boiling point of the solution is : ( K_(b) for H_(2)O = 0.52K kg/mol)

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% Ionised. The boiling point in the solutioin is ( K_(b) for H_(2)O=0.52K kg mol)

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25 % ionized. The boilling point of solution is ( K_(b) for H_(2)O=0.52K kg//mol )

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The Boiling point of the solution is (K_(b) of H_(2)O=0.52K kg mol^(-1))

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The boiling point of the solution is (K_(b) for H_(2)O = 0.52 K kg//mol) :

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The boiling point of the solution is (K_(b) for H_(2)O = 0.52 K kg//mol) :

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The boiling point of the solution is (K_(b) for H_(2)O = 0.52 K kg//mol) :

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )