" 34."int_(0)^( pi/2)log(sin2x)dx=-(pi)/(2)(log2)

int_(0)^(pi//2)log(sinx)dx=

Show that int_(0)^((pi)/(2))log(sin2x)dx=-(pi)/(2)(log2)

int_(0)^(pi//2)log(tanx)dx=

int_(0)^((pi)/(2))log(sin x)dx

int_(0)^(pi)log sin^(2)x dx=

int_(0)^(pi)log sin^(2)x dx=

int_(0)^(pi//2) log sin x dx =

Statement-1: int_(0)^(pi//2) x cot x dx=(pi)/(2)log2 Statement-2: int_(0)^(pi//2) log sin x dx=-(pi)/(2)log2

int_(0)^((pi)/(2))log(tanx)dx