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[" Q."20" of "25],[sum(n=1)^(1000)int(n-...

[" Q."20" of "25],[sum_(n=1)^(1000)int_(n-1)^(n)e^(x-[x])dx" where "[x]" is the greatest "],[" integer,is "]

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sum_(n=1)^(100) int_(n-1)^(n) e^(x-[x])dx=

sum_(n = 1)^(1000) int_(n - 1)^(n) e^(x-[x]) dx , whose [x] is the greatest integer function, is :

The value of sum_(n=1)^100 int_(n-1)^n e^(x-[x])dx =

The value of sum_(n=1)^1000 int_(n-1)^n e^(x-[x])dx , where [x] is the greatest integer function, is (A) (e^1000-1)/1000 (B) (e-1)/1000 (C) (e^1000-1)/(e-1) (D) 1000(e-1)

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int_(-1)^(41//2)e^(2x-[2x])dx , where [*] denotes the greatest integer function.

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Evaluate sum_(n=1)^(1000)int_(n-1)^(n)|cos2pix|dx