[" 41."4x^(2)-4a^(2)x+(a^(4)-b^(4))=0," [CBSE "2015]]

Solve 4x^(2)-4ax+(a^(2)-b^(2))=0.

Solve the following quadratic for x: 4x^(2)-4a^(2)x+(a^(4)-b^(4))=0

Solve by factorization: 4x^(2)-4a^(2)x+(a^(4)-b^(4))=0

Solve each of the following quadratic equations: 4x^(2)-4a^(2)x+(a^(4)-b^(4))=0

4x^(2)-4x-80=0

Solve the following quadratic equation by factorization method: ( ) x^(2)-2ax+a^(2)-b^(2)=0(ii)x^(2)-4ax+4a^(2)-b^(2)=0(iii)4x^(2)-4ax+(a^(2)-b^(2))=0(iv)4x^(2)-4a^(2)x+(a^(4)-b^(4))=

The biquadratic equation, two of whose roots are 1+i , 1-sqrt(2) is A) x^(4)-4x^(3)+5x^(2)-2x-2=0 B) x^(4)-4x^(3)-5x^(2)+2x+2=0 C) x^(4)+4x^(3)-5x^(2)+2x-2=0 D) x^(4)+4x^(3)+5x^(2)-2x+2=0

If int (x^(8)-12x^(4)+4)/(x^(4)-4x^(2)+2)dx = x^(a)/a + (4x^(b))/b +2x+C , then the value of (a+b) is

Factorise : 4a^(2) - 4ab+ b^(2) - 4x^(2)