`0.116 g` of `C_(4)H_(4)O_(4) (A)` in neutralised by `0.074 g` of `Ca(OH)_(2)`. Hence protonic hydrogen `(H^(o+))` in `(A)` will be

1 g of an acid C_(6)H_(10)O_(4) is completely neutralised by 0.768 g KOH . Calculate the number of neutralizable protons in acid.

NaHC_(2)O_(4) is 0.1 M when neutralised with NaOH. Hence, it is ...... when oxidised with MnO_(4-)//H^(+) .

One gram of the acid C_(6) H_(10) O_(4) requires 0.768 g of KOH for complete neutralisation. How many neutralisable hydrogen atoms are in this molecule?

One gram of the acid C_(6) H_(10) O_(4) requires 0.768 g of KOH for complete neutralisation. How many neutralisable hydrogen atoms are in this molecule?

C_(7)H_(6)O_(3) + C_(4)H_(6)O_(3) rightarrow C_(9)H_(8)O_(4) + C_(2)H_(4)O_(2) What is the percent yield if 0.85 g of aspirin is formed in the reaction of 1.00 g of salicylic acid with excess acetic anydride ? {:("Substance", "Molar Mass"), (C_(7)H_(6)O_(3), 138.12g.mol^(-1)), (C_(4)H_(6)O_(3), 102.09g.mol^(-1)), (C_(9)H_(8)O_(4), 180.15g. mol^(-1)), (C_(2)H_(4)O_(2), 60.05g.mol^(-1)):}

A solution of 0.4 g sample of H_(2)O_(2) reacted with 0.632 g of KMnO_(4) in presence of sulphuric acid. The percentage purity of the sample of H_(2)O_(2) is :

100 " mL of " 0.2 M Kal (OH)_(2)CO_(3) solution is completely neutralised by a standard solution of (M)/(4)H_(2)C_(2)O_(4) . Which of the following is/are wrong?