The angle `theta` through which a pulley turns with time t is specified by the function`theta = t^2 + 3t -5`. Find the angular velocity `omega = (d theta)/(dt)` at `t = 5 "sec"`.

An angle theta through which a pulley turns with time 't' is completed by theta = t^(2) + 3t - 5 sq. cms / min Then the angular velocity for t = 5 sec.

The angular displacement theta radians of a fly wheel varies with time t seconds and follow the equation theta = 9t^(2) - 2t^(3) . Determine the angular velocity and acceleration of the fly wheel when time t =1 seconds and (ii) The time when the angular acceleration is zero.

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the velocity at t=2 sec

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then, its angular velocity at t=2 sec is …… rad s^(-1)

The angular displacement of a body is given by theta = 2t^(2) + 5t -3 . Find the value of the angular velocity and angular acceleration when t = 2s.

The angular displacement of particle (in radian) is given by theta=t^(2) + t . Calculate angular velocity at t=2 second.

The displacement s of a particle at time t is given by s = t^3 -4 t^2 -5t. Find the velocity and acceleration at t=2 sec

A particle is at rest, It starts rotating about a fixed point. Its angle of rotation (theta) with time (t) is given by the relation : theta = (6t^3)/(15) - (t^2)/(2) where theta is in radian and t is seconds. Find the angular velocity and angular acceleration of a particle at the end of 6 second.

The angular position of a point on the rim of a rotating wheel is given by theta=4t^(3)-2t^(2)+5t+3 rad. Find (a) the angular velocity at t=1 s , (b) the angular acceleration at t=2 s . (c ) the average angular velocity in time interval t=0 to t=2 s and (d) the average angular acceleration in time interval t=1 to t=3 s .