A stone is thrown vertically up and the height `s` reached in time `t` is given by `s=80t-16t^2`. The stone reaches the maximum height in time `t` =

A stone is thrown up vertically. The height it reaches at time t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in time t seconds is given by

A stone is thrown up vertically and the height x feet reached by it in time t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in time (seconds)

A stone is thrown vertically upwards and the height x ft, reached by the stone in t seconds is given by x=80t-16t^(2) . The stone reaches the maximum height in

A stone is thrown up vertically and the height x ft it reached in t seconds is x=(80)t -(16)t^(2) . It reached the maximum height in time t=

If a ball is thrown vertically upward and the height 's' reached in time 't' is given by s = 22 t - 11 t^(2) , then the total distance travelled by the ball is

A ball is thrown vertically upwards which satisfies the equation S=80t-16t^2 . Find the time required to reach the maximum height.

A stone thrown vertically upwards satisfies the equations s = 80t –16t^(2) . The time required to reach the maximum height is

A stone is thrown vertically upwards from the top of a tower 64m high according to the law of motion given by s=48t-16t^(2) . The greatest height attained by the stone above ground is