Two springs of constants `k_1` and `k_2` have equal maximum velocities, when executing simple harmonic motion. The ratio of their amplitudes (masses are equal) will be

Two springs, of spring constants k_(1) and K_(2) , have equal highest velocities, when executing SHM. Then, the ratio of their amplitudes (given their masses are in the ratio 1:2 ) will be

Two springs, of spring constants k_(1) and K_(2) , have equal highest velocities, when executing SHM. Then, the ration of their amplitudes (given their masses are in the ratio 1:2 ) will be

The maximum velocity a particle, executing simple harmonic motion with an amplitude 7 mm, 4.4 m//s. The period of oscillation is.

Two particles A and B of equal masses are suspended from two massless springs of spring constants K_(1) and K_(2) respectively. If the maximum velocities during oscillations are equal. the ratio of the amplitude of A and B is

The maximum velocity of a particle executing simple harmonic motion with an amplitude 7 mm is 4.4 m/s. The period of oscillation is.

The figure shows a mass M attached to a series arrangement of two springs of spring constants k_(1) and k_(2) where k_(2) = 2k_(1) . If the mass M oscillates in simple harmonic motion with amplitude A, the amplitude of the point O is (alphaA)/(beta) . Find beta-alpha .

Two bodies P & Q of equal mass are suspended from two separate massless springs of force constant k_(1) & k_(2) respectively. If the maximum velocity of them are equal during their motion, the ratio of amplitude of P to Q is :