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KMnO(4) reacts with oxalic acid accordin...

`KMnO_(4)` reacts with oxalic acid according to the equation:
`2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to2Mn^(2+)+10CO_(2)+8H_(2)O` 20mL of 0.1M `KMnO_(4)` will react with:

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KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10Co_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

KMnO_(4) react with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O , here 20 ml of 0.1 M KMnO_(4) is equivalemt to

KMnO_4 reacts with oxalic acid according to the equation 2MnO_4 + 5C_2 O_4^(2-) + 16H^+ rarr 2Mn^(2+) + 10CO_2 + 8H_2O Here, 20mL of 0.1M KHMnO_4 is equivalent to :

KMnO_4 reacts with oxalic acid according to the equation 2MnO_4 + 5C_2 O_4^(2-) + 16H^+ rarr 2Mn^(2+) + 10CO_2 + 8H_2O Here, 20mL of 0.1M KHMnO_4 is equivalent to :

In the redox reaction, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O 20mL of 0.1 M KMnO_(4) reacts quantitatively with :