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The expression ((1+i)^n)/((1-i)^(n-2)) ...

The expression `((1+i)^n)/((1-i)^(n-2))` equals

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For positive integers n_1,n_2 , the value of the expression : (1+i)^(n_1)+(1+i^3)^(n_1) +(1+i^5)^(n_2)+ (1+i^7)^(n_2) , where i= sqrt(-1) is a real number if and only if :

For positive integer n_1,n_2 the value of the expression (1+i)^(n1) +(1+i^3)^(n1) (1+i^5)^(n2) (1+i^7)^(n_20), where i=sqrt-1, is a real number if and only if (a) n_1=n_2+1 (b) n_1=n_2-1 (c) n_1=n_2 (d) n_1 > 0, n_2 > 0

For positive integer n_1,n_2 the value of the expression (1+i)^(n1) +(1+i^3)^(n1) (1+i^5)^(n2) (1+i^7)^(n_20), where i=sqrt-1, is a real number if and only if (a) n_1=n_2+1 (b) n_1=n_2-1 (c) n_1=n_2 (d) n_1 > 0, n_2 > 0

For positive integers n_(1) and n_(2) the value of the expression (1+i)^(n_(1))+(1+i^(3))^(n_(1))+(1+i^(5))^(n_(2))+(1+i^(7))^(n_(2)) is a real number if and only if

For positive integers n_(1), n_(2) the value of the expression (1+i)^(n_(1)) + (1+ i^(3))^(n_(1)) + (1+ i^(5))^(n_(2)) + (1+ i^(7))^(n_(2)) , where i= sqrt-1 is a real number if and only if

If n is an odd integer, i= sqrt -1 then [ (1 + i)^(6n) + (1 - i)^(6n) ] is equal to