A capacitor of capacity `C_(1)` is charged to the potential of `V_(0)`. On disconnecting with the battery, it is connected with a capacitor of capacity `C_(2)` as shown in the adjoining figure. The ratio of energies before and after the connection of switch S will be

A capacitor of capacity C_(1) is charged to the potential of V_(0) . On disconnecting with the battery, it is connected with a capacity C_(2) as shown in the adjoining figure. The ratio of energies before and after the connection of switch S will be

A capacitor of capacitnace C is charged to a potential difference V and then disconnected from the battery. Now it is connected to an inductor of inductance L at t=0. Then

A capacitor of capacity C_(1) = 1 muF is charged to a potential of 100 V. The charging battery is then removed and it is connected to another capacitor of capacity C_(2) = 2 muF . One plate of C_(2) is earthed as shown in figure. The charges on C_(1) and C_(2) in steady state will be

A capacitor of capacity C_(1) = 1 muF is charged to a potential of 100 V. The charging battery is then removed and it is connected to another capacitor of capacity C_(2) = 2 muF . One plate of C_(2) is earthed as shown in figure. The charges on C_(1) and C_(2) in steady state will be

A capacitor C is charged to a potential V by a battery. It is then disconnected from the battery and again connected with its polarity reversed to the battery

A capacitor C is charged to a potential V by a battery. It is then disconnected from the battery and again connected with its polarity reversed to the battery

A capacitor of capacity C_(0) is charged to certain potential and enrgy stored in it is U_(0) . Now this capacitor is connected in parrallel to uncharged capacitor of capacitance. C . Find the loss of energy.

A capacitor of capacitance C_(0) is charged to a potential V_(0) and is connected with another capacitor of capacitance C as shown. After closing the switch S, the common potential across the two capacitors becomes V, The capacitance C is given by