n identical drops each of radius r combine into a big drop of radius R.The energy loss during this formation is 3E where E is the energy of the bigger drop.The value of 'n' is

When ‘n’ identical droplets are combined to form a big drop, then the energy will be released If n identical small droplets each of radius r merge to form a big drop of radius R and the energy released in this process is absorbed by the big drop so as to increase its kinetic energy then the speed of the big drop (T be the surface tension and d be the density of the liquid droplets)

When ‘n’ identical droplets are combined to form a big drop, then the energy will be released If n identical small droplets each of radius r merge to form a big drop of radius R and the energy released in this process is absorbed by the big drop then rise in temperature (T be the surface tension, d be the density and S be the specific heat of the liquid droplets)

n number of identical drops combine to form a big drop. If E be the energy of each small drop, then what is the energy of this bigger drop?

n droplets of equal size of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to

n droplets of equal size and each of radius r coalesce to form a bigger drop of radius R. the energy liberated is equal to

A large number of liquid drops each of radius 'a' coalesce to form a single spherical drop of radius b. The energy released in the process is converted into kinetic energy of the big drops formed. The speed of big drop will be

When a big drop of water is formed from n small drops of water, the energy loss is 3E, where, E is the energy of the bigger drop. If the radius of the bigger drop is R and r is the radius of the smaller drop, then number of smaller drops (n) is

n' droplets of equal of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to ( T = Surface tension of water )