" (A) "((1)/(2)x+(1)/(3)y)^(15)" ,जब "x=8,y=9

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

x+y+z = 15 if 9, x,y,z,a are in A.P., while (1)/( x) + ( 1)/( y) + ( 1)/( z) = ( 5)?( 3) if 9, x,y,z,a are in H.P., then the value of a will be :

(x+1)/(2)+(y-1)/(3)=8;(x-1)/(3)+(y+1)/(2)=9

Solve for x and y : (x+1)/(2)+(y-1)/(3)=9, (x-1)/(3)+(y+1)/(2)=8 .

(x+1)/(2)+(y+1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 then x=………

Solve the following equations: (x+1)/(2)+(y-1)/(3)=8" and "(x-1)/(3)+(y+1)/(2)=9

Solve by the elimination method: (x+1)/(2)+(y-1)/(3)=9 and (x+1)/(3)+(y-1)/(2)=8

x+y+z=15 if 9, x, y, z, a are in A.P. while (1)/(X)+(1)/(Y)+(1)/(Z)=(5)/(3)if9,X, Y, Z, a are in H.P., then the value of a will be -

If 1,m ,n are the direction cosines of the line of shortest distance between the lines (x-3)/(2) = (y+15)/(-7) = (z-9)/(5) and (x+1)/(2) = (y-1)/(1) = (z-9)/(-3) then :