" (ii) "2sin^(2)theta+sin^(2)2 theta=2

The root (s) of the expression 2sin^(2)theta+sin^(2)2 theta=2is

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

The number of values of theta in [(-3pi)/(2), (4pi)/(3)] which satisfies the system of equations. 2 sin^(2) theta + sin ^(2) 2 theta = 2 and sin 2 theta + cos 2 theta = tan theta is

The number of values of theta in [(-3pi)/(2), (4pi)/(3)] which satisfies the system of equations. 2 sin^(2) theta + sin ^(2) 2 theta = 2 and sin 2 theta + cos 2 theta = tan theta is

If cos theta+cos^(2)theta=1 then sin^(2)theta+2sin^(2)theta+sin^(2)theta=