Home
Class 11
CHEMISTRY
According to Le Chatelier's principle, o...

According to Le Chatelier's principle, on applying any external force to desturb equilibrium, the reaction moves in that direction in which effect of exteranal force is minimised as far as possible. A container whose volume is V contains an equilibrium mixture that contains 2 moles each of `PCl_(5)`, `PCl_(3)` and `Cl_(2)`n (all gases). The pressure is 3atm and temperature is T. A certain amount of `Cl_(2)(g)` is now introduced keeping the pressure and temperature constant untill the equilbrium volume changes to 2 V.
`PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`. The moles `Cl_(2)` that was added is :

Promotional Banner

Similar Questions

Explore conceptually related problems

According to Le Chatelier's principle, on applying any external force to desturb equilibrium, the reaction moves in that direction in which effect of exteranal force is minimised as far as possible. A container whose volume is V contains an equilibrium mixture that contains 2 moles each of PCl_(5) , PCl_(3) and Cl_(2) n (all gases). The pressure is 3atm and temperature is T. A certain amount of Cl_(2)(g) is now introduced keeping the pressure and temperature constant untill the equilbrium volume changes to 2 V. PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) . The equilibrium constant K of the reaction :

A container whose volume is V contains an equilibrium mixture that consists of 2 mol each of PCl_5, PCl_3 and Cl_2 (all as gases) . The pressure is 30.3975 kpa and temperature is T. A certain amount of Cl_2 (g) is now introduced keeping the pressure and temperature constant until the equilibrium volume is 2V. Calculate the amount of Cl_2 that was added and the value of k_p .

A container of volume V L contains an equilibrium mixture that consists of 2 mol each of gaseous PCl_(5), Pcl_(3) and Cl_(2) at 3 atm T K . Some Cl_(2) is added unitl the volume is double keeping P and T constant. Calculate moles of Cl_(2) added and K_(p) for PCl_(5) rarr PCl_(3)+Cl_(2)

A container of volume V L contains an equilibrium mixture that consists of 2 mol each of gaseous PCl_(5), PCl_(3) and Cl_(2) at 3 atm, T K . Some Cl_(2) is added until the volume is double, keeping P and T constant. Calculate moles of Cl_(2) added and K_(p) for PCl_(5) rarr PCl_(3)+Cl_(2)

The pressure at which equilibrium constant in terms of pressures is found to be equal to that in terms of mole fraction for the equilibrium, PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2) (g)

At a given temperature the equilibrium constant for the reaction of PCl_(5)hArrPCl_(3)+Cl_(2) is 2.4xx10^(-3) . At the same temperature, the equilibrium constant for the reaction PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g) is :

1 mol PCl_(2)(g) is heated in a closed container of 2 litre capacity. If at equilibrium, the quantity of PCl_(5)(g) be 0.2 mol then calculate the value of equilibrium constant for the given reaction, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) .