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If A+B=225^(@) then the value of (cotA...

If A+B`=225^(@)` then the value of
`(cotA)/(1+cotA).(cotB)/(1+cotB)` is

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If A+B=225^(@) , then find the value of (cotA)/(1+cotA)xx(cot B)/(1+cotB)

If A+B=225^(@) , then find the value of (cotA)/(1+cotA)xx(cot B)/(1+cotB)

If A+B=225^(@) , then find the value of (cotA)/(1+cotA)xx(cot B)/(1+cotB)

If A+B=225^(@) , prove that: (cotA)/(1+cotA) xx (cotB)/(1+cotB) = 1/2

If A+B=225^(@) than prove that (cot A)/(1+cotA). (cot B)/(1+cotB)=(1)/(2)

If A+B=225^(@) then (cotA)/(1+cotA).(cotB)/(1+cotB) = ………….

cot(A-B)=(cotA.cotB+1)/(cotB-cotA)

cot(A+B)=(cotA.cotB-1)/(cotB+cotA)

cot(A-B)=(cotA.cotB+1)/(cotB-cotA)

If A+B+C=180^@ then the value of (cotB+cotC)(cotC+cotA)(cotA+cotB) will be