In YDSE `a = 2mm`, D = 2m, `lambda = 500` mm. Find distance of point on screen from central maxima where intensity becomes `50%` of central maxima

In YDSE, D = 1 m, d = 1 mm , and lambda = 5000 nm . The distance of the 100th maxima from the central maxima is

In YDSE, D = 1 m, d = 1 mm , and lambda = 5000 nm . The distance of the 100th maxima from the central maxima is

In a YDSE, D = 1m, d = 1mm and lambda = 1//2 mm Find a distance between the first and central maxima on the screen.

In a YDSE, D = 1 M, d = 1 mm, and lambda = 1//2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

In a YDSE, D = 1 M, d = 1 mm, and lambda = 1//2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

In Young's experiment the slits, separated by d = 0.8 mm , are illuminated with light of wavelength 7200 Å, Interference pattern is obtained on a screen D = 2 m from the slits. Find minimum distance from central maximum at which the a average intensity is 50% if of maximum?

In Young's experiment the slits, separated by d = 0.8 mm , are illuminated with light of wavelength 7200 Å, Interference pattern is obtained on a screen D = 2 m from the slits. Find minimum distance from central maximum at which the a average intensity is 50% if of maximum?

In a YDSE experiment, d = 1mm, lambda = 6000Å and D= 1m. The minimum distance between two points on screen having 75% intensity of the maximum intensity will be

In a YDSE experiment, d = 1mm, lambda = 6000Å and D= 1m. The minimum distance between two points on screen having 75% intensity of the maximum intensity will be