बिंदु (-1, -5, -10) की दूरी उस बिंदु से ज्ञात कीजिए , जहाँ पर रेखा `((x-2)/3)=((y+1)/4)=((z-2)/12)`, तल `x-y+z=5` से मिलती है ।

Find the distance of the points (-1, -5, -10) form the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and plane x-y+z=5

The distance between the point (-1, -5, -10) and the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) with the plane x-y+z=5 is -

The distance between the point (-1, -5, -10) and the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) with the plane x-y+z=5 is

Find the distance between the point (-1, -5, -10) and the point of intersection of line (x-2)/(3) = (y+1)/(4) = (z-2)/(12) and plane x-y + z =5

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and plane x-y+z=5 .

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5

Find the distance of the point (-1, -5, -10) from the point of intersection of the (x-2)/3=(y+1)/4=(z-2)/12 and the plane x-y + z= 5.

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.