The following is the p.d.f of continuous random variable X. `f(x) = (x)/(8), 0 lt x lt 4`
=0 , otherwise.
Find the expression for c.d.f of X

The following is the p.d.f of continuous random variable X. f(x) = (x)/(8), 0 lt x lt 4 =0 , otherwise. Also , find its value at x = 0.5 , 1.7 and 5

The following is the p.d.f (Probability Density Function ) of a continous random variable X : f(x) = (x)/(32), 0 lt x lt 8 = 0 , otherwise Find the expression for c.d.f (Cumulative Distribution Function ) of X

The p.d.f of a continous random variable X is f(x)=x/8, 0 lt x lt 4 =0 , otherwise Then the value of P(X gt 3) is

The p.d.f of a continous random variable X is f(x)=x/8, 0 lt x lt 4 =0 , otherwise Then the value of P(X gt 3) is

If the p.d.f of a continuous random variable X is f(x)=kx^(2)(1-x), 0 lt x lt 1 = 0 otherwise Then the value of k is

If the p.d.f of a continuous random variable X is f(x)=kx^(2)(1-x), 0 lt x lt 1 = 0 otherwise Then the value of k is

The p.d.f of a continuous random variable X is f(x) = (x^(2))/(3), - 1 lt x lt 2 0 = otherwise Then the c.d.f of X is

Thep.d.f of a continous random variable X is f(x) = (x^(2))/(3), - 1 lt x lt 2 0 = otherwise Then the c.d.f of X is

The p.d.f. of a continuous random variable X is f(x) = K/(sqrt(x)), 0 lt x lt 4 = 0 , otherwise Then P(X ge1) is equal to