If n is an even natural number, then `sum_(r=0)^n (-1)^r/(.^nC_r)` equals

If n is an odd natural number, then sum_(r=0)^n (-1)^r/(nC_r) is equal to

If n is an odd natural number, then sum_(r=0)^n (-1)^r/(nC_r) is equal to

If n is an even natural number , then sum_(r=0)^(n) (( -1)^(r))/(""^(n)C_(r)) equals

If n is an even natural number , then sum_(r=0)^(n) (( -1)^(r))/(""^(n)C_(r)) equals

If n is an odd natural number,then sum_(n)^(n)((-1)^(r))/(nC_(r)) is equal to

let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to

let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to

Let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers. Then sum_(r=1)^(n)(S_(r))/( S_(r )) equals :