Assertion: The fringe visibility will be maximum when amplitude of light waves from two coherent sources is exactly equal.
Reason: Fringe visibiltgiy `V=(I_("max"))/(I_("min"))`

If the ratio of the intensity of two coherent sources is 4 then the visibility [(I_(max)-I_(min))//(I_(max)+I_(min))] of the fringes is

If the ratio of the intensity of two coherent sources is 4 then the visibility [(I_(max)-I_(min))//(I_(max)+I_(min))] of the fringes is

If the ratio of the intensity of two coherent sources is 4 then the visibility [(I_(max)-I_(min))//(I_(max)+I_(min))] of the fringes is

Two coherent sources of intensity ratio beta interfere, then (I_(max)-I_(min))/(I_(max)+I_(min)) is

Two coherent sources of intensity ratio a interfere. The value of (I_("max")-I_(min))/(I_("max")+I_(min)) is ....

Assertion (A): For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the amplitudes of light waves emerging from the two sources should be equal. Reason (R): For interference, the sources must be coherent.

The two coherent sources with intensity ratio beta produce interference. The fringe visibility will be

The two coherent sources with intensity ratio beta produce interference. The fringe visibility will be

The ratio of amplitude of two waves producing interference pattern is 1 : 4. Find I_("max") to I_("min") and fringe visiblity.