[" If the function "f(x)=(4,sin^(2)x-1)^(n)(x^(2)-x+1)],[n in N," has a local maximum at "x=pi/6," then "'n']

If the function f(x)=(4sin ^2 x-1)^n(x^2-x+1)n in N has a local maximum at x= pi //6 then n

The function f(x)=(4sin^(2)x-1)^(n)(x^(2)-x+1),n in N has a local minimum at x=(pi)/(6). Then (a) n is any even number (b) n is an odd number ( ) n is odd prime number (d) n is any natural number

The function f(x)=(4sin^2x−1)^n (x^2−x+1),n in N , has a local minimum at x=pi/6 . Then (a) n is any even number (b) n is an odd number (c) n is odd prime number (d) n is any natural number

The function f(x)=(4sin^2x−1)^n (x^2−x+1),n in N , has a local minimum at x=pi/6 . Then (a) n is any even number (b) n is an odd number (c) n is odd prime number (d) n is any natural number

The function f(x)=(4sin^2x−1)^n (x^2−x+1),n in N , has a local minimum at x=pi/6 . Then (a) n is any even number (b) n is an odd number (c) n is odd prime number (d) n is any natural number

let f(x)=(x^(2)-1)^(n)(x^(2)+x-1) then f(x) has local minimum at x=1 when

The function f(x)=(x^(2)-4)^(n)(x^(2)-x+1),n in N assumes a local mininum values of n Then find the possible values of n

The function f(x)=(x^2-4)^n(x^2-x+1),n in N , assumes a local minimum value at x=2. Then find the possible values of n

The function f(x)=(x^2-4)^n(x^2-x+1),n in N , assumes a local minimum value at x=2. Then find the possible values of n