In a right-angled triangle, the square of hypotenuse is equal to the sum of the squares of the two sides. Given that `angleB` of `triangleABC` is an acute angle and `AD_|_BC` . Prove that `AC^2= AB^2 + BC^2 -2BC.BD`.

In triangleABC , angleB is an acute angle and AD botBC . Prove that AC^2= AB^2+BC^2-2BC.BD.

Prove that "In a right angled triangle the square of hypotenuse is equal to the sum of the square of the other two sides".

Prove that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Prove that is a right angle triangle, the square of the hypotenuse is equal the sum of the squares of other two sides.

Prove that, in a right-angled triangle, the square of hypotenuse is equal to the sum of the square of remaining two sides.

Prove that, in a right-angled triangle, the square of hypotenuse is equal to the sum of the square of remaining two sides.

In fig. /_B of /_\ABC is an acute angle and AD _|_ BC ; prove that AC^2 = AB^2 + BC^2 - 2 BC xx BD

Prove by vector method, that in a right angled triangle the square of h the hypotenuse is equal to the sum of the square of the other two sides.

Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Use the above theorem, in the following. If ABC is an equilateral triangle with AD bot BC , then prove that AD^(2) = 3DC^(2) .