Show : `(1+tan^2theta)(1+sintheta)(1-sintheta) = 1`

(1+tan^(2)theta)(1-sintheta)(1+sintheta)= ………… .

Prove the following trigonometric identities : cot^2theta-1/(sin^2theta)=-1 (ii) (1+tan^2theta)(1+sintheta)(1-sintheta)=1

Prove the following : (All angles are acute angles.) (1+tan^(2)theta)(1+sintheta)(1-sintheta)=1

Prove that (1+tan^2theta)(1-sintheta)(1+sintheta)=1 .

Smlplify : (1+tan^(2)theta)(1-sintheta)(1+sintheta)

What is the value of (1+tan^2theta)(1-sintheta)(1+s in\ theta) ?

Show that: (a) (1+tan^(2)theta)(1-sintheta)(1+sintheta)=1 (b) (sintheta)/(1+costheta)+(1+costheta)/(sintheta)=2cosectheta

Simplify: (1+tan^(2)theta)(1-sintheta)(1+sintheta)

Simplify: (1+tan^(2)theta)(1-sintheta)(1+sintheta)

Prove that: (i) (costheta)/(1-sintheta)=(1+sintheta)/(costheta) (ii) (1+costheta-sin^(2)theta)/(sintheta+sinthetacostheta)=cottheta (iii) 1+(tan^(2)theta)/(1+sectheta)=sectheta