A thread of mercury of 10.2 g is in a tube of uniform cross-section `0.1cm^2`. Calculate the length of the thread. The density of mercury is `13.6(g)/(cm^3)`.

A verticle U-tube of uniform inner cross section contains mercury in both sides of its arms. A glycerine (density =1.3g//cm^3) column of length 10 cm is introduced into one of its arms. Oil of density 0.8 gm//cm^3 is poured into the other arm until the upper surfaces of the oil and glycerine are at the same horizontal level. Find the length of the oil column, density of mercury =13.6 g//cm^3

What volume will 250 g of mercury occupy ? (Density of mercury =13.6 g cm^(-3) )

A U-tube of uniform cross-section contains some mercury. If water is poured into one of the limbs up to a height of 13.4cm, then find the rise in the mercury level in the other limb. The density of mercury = 13.4g*cm^(-3) .

A vertical U tube of uniform cross section contains mercury in both of its arms. A glycerine (d=1.3g//cm^(3)) column of length 10 cm is introduced into one of the arms. Oil of density 0.8g//cm^(3) is poured in the other arm until the upper surfaces of the oil and glycerine are in the same horizontal level. Find the length of oil column. Densit of mercury is 13.6g//cm^(3) .

Each side of an iron cube is 5 cm. This cube floats on mercury. What height of the cube remains above the surface of mercury? To cover the cube, if water is poured over mercury, then what will be the height of the water column? The density of iron is 7.2g*cm^(-3) and the density of mercury is 13.6g*cm^(-3) .

The column of mercury in a barometer is 76 cm Hg. Calculate the atmosphere pressure I the density of mercury =13600kgm^(-3) (Take g=10ms^(-2) )

A U-tube of uniform cross-section holds 1 kg of pure mercury and 0.2 kg of water in equilibrium. The diameter of cross-section is 1.2 cm. Relative density of mercury is 13.6. If the system in equilibrium is slightly disturbed, the period of oscillation of the liquid column in the tube will be (take g=10ms^(-2) )