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If theta is real then the modulus of 1/(...

If `theta` is real then the modulus of `1/(1+costheta+isintheta)` is

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If theta is real then the modulus of (1)/(1 + cos theta + isin theta) is

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^6 =

(1+costheta-isintheta)^4 =

|1+costheta+isintheta|=

(1-costheta+isintheta)^(6)

(1+costheta-isintheta)^(n)

Find (costheta+isintheta)^n

The real part of (1-costheta + 2isintheta)^-1 is

The amplitude of 1+costheta+isintheta is