If the curve `ax^(2) + 3y^(2) = 1 and 2x^2 + 6y^2 = 1` cut each other orthogonally then the value of 2a :

The curves 2x^(2) + 3y^(2) = 1 and cx^(2) + 4y^(2) = 1 cut each other orthogonally then the value of c is:

If the curves ax^(2) + by^(2) =1 and a_(1) x^(2) + b_(1) y^(2) = 1 intersect each other orthogonally then show that (1)/(a) - (1)/(b) = (1)/(a_(1)) - (1)/(b_(1))

The curves ax^(2)+by^(2)=1 and Ax^(2)+B y^(2) =1 intersect orthogonally, then

If curve y = 1 - ax^2 and y = x^2 intersect orthogonally then the value of a is

If curve y = 1 - ax^2 and y = x^2 intersect orthogonally then the value of a is

For the circles x^2 + y^2 - 2x + 3y + k = 0 and x^2 + y^2 + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be

For the circles x^(2) + y^(2) - 2x + 3y + k = 0 and x^(2) + y^(2) + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be