The increase in pressure required to decrease the 200 L volume of a liquid by 0.008 % in kPa is (Bulk modulus of the liquid = 2100 M Pa is )

An increases in pressure required to decreases the 200 litres volume of a liquid by 0.004% in container is: (bul modulus of the liquid =2100MPa )

An increases in pressure required to decreases the 200 litres volume of a liquid by 0.004% in container is: (bul modulus of the liquid =2100MPa )

An increases in pressure required to decreases the 200 litres volume of a liquid by 0.004% in container is: (bul modulus of the liquid =2100MPa )

The increase in pressure in kPa requried to decrease 200 litre volume of a liquid by 0.004% is (bulk modulus of the liquif = 2100 Mpa)

The increase in pressure required to decrease volume by 0.005% of 150 litre liquid (in kPa) is (Bulk modulus of liquid, B=3*10^9 N/m^2 )

The increase in pressure required to decrease volume by 0.005% of 150 litre liquid (in kPa) is (Bulk modulus of liquid, B=3 x 10^9 N/m^2 )

What increase in pressure is required to decrease the volume of 200 litre of water by 0.004 percent? Given bulk modulus of water is 2100 Mpa.

Find the increase in pressure required to decrease the volume of given mercury by 0.001 % [ Bulk modulus of mercury = 2.8 xx 10^(10) N//m^(2)]

The extra pressure required to decrease the volume of a liquid of Bulk modulus 2.5 GPa by 0.01% is

The extra pressure required to decrease the volume of a liquid of Buik modulus 2.5 GPa by 0.01% is