If displacement S at time t is `S=2t^(3) +6t`, then velocity is always

If displacement S at time t is S=-t^(3)+3t^(2)+5 , then velocity at time t=2 sec is

If displacement S at time t is S=10t-5t^(2) , then velocity at time t is

If displacement of particle is s=t^(3)-6t^(2)+9t+15, then velocity of the particle at beginning is

If displacement S at time t is S=t^(3)-3t^(2)-15t+12 , then acceleration at time t=1 sec is

The rate of change of displacement with respect to time is known as velocity.If displacement of a particle is s=3t^(2)+4t+5 then velocity as a function of time

[" The rate of change of "],[" displacement with respect to "],[" time is known as velocity.If "],[" displacement of a particle is "],[s=3t^(2)+4t+5" then velocity as "],[" a function of time "]

If the displacement s at a time t is given by s = sqrt(1-t) , than the velocity is

A particle moves along a straight line such that its displacement s at any time t is given by s=t^3-6t^2+3t+4m , t being is seconds. Find the velocity of the particle when the acceleration is zero.

If displacements of a particle varies with time t as s = 1/t^(2) , then.

The displacement s of a particle at time t is given by s = t^3 -4 t^2 -5t. Find the velocity and acceleration at t=2 sec