आगमन विधि से सिद्ध कीजिए `1+4+7+…+(3n-2)=(1)/(2)n(3n-1)` सभी `n in N` के लिए।

If P(n) :1+4+7…….+(3n-2)=(1)/(2)n(3n-1) .Verify P(n) for n =1,2.

Prove by the principle of mathematical induction that 1+4+7+…..+(3n-2)=1/2n(3n-1),AA n in N .

1/1.4+1/4.7+1/7.10+...+1/((3n-2)(3n+1))=n/((3n+1)) forall n in N.

By using the principle of mathematical induction , prove the follwing : (1)/(1.4) + (1)/(4.7) + (1)/(7.10) + ………..+ (1)/((3n - 2)(3n+1)) = (n)/(3n + 1) , n in N

1.3 + 2.4 + 3.5 + …… + n(n+2) =( n(n+1)(2n+7))/6

Using the principle of mathematical induction, prove that : 1. 2. 3+2. 3. 4++n(n+1)(n+2)=(n(n+1)(n+2)(n+3))/4^ for all n in N .

Using the principle of mathematical induction, prove that : 1. 2. 3+2. 3. 4++n(n+1)(n+2)=(n(n+1)(n+2)(n+3))/4^ for all n in N .

1.2+2.3+3.4+…………..+n(n+1)=n/3(n+1)(n+2) forall n in N.

1^(3)+2^(3)+3^(3)+.....+n^(3)=(n(n+1)^(2))/(4), n in N