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A bar of mass m resting on a smooth hori...

A bar of mass m resting on a smooth horizontal plane starts moving due to force
`|F| =(mg)/9`. The magnitude of force remains
constant with time. The force vector makes an angle `theta` with the horizontal which varies with the distance covered as `theta =Cx`. if the
constant , `C=10 (("degree")/("meter"))`, then the speed of
the bar , when `theta` becomes equal to `30^@` for the first time is, (Take , `g =10 m//s^2`)

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