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If x/a+y/b=1 intersects 5x^2+5y^2 +5bx ...

If `x/a+y/b=1` intersects `5x^2+5y^2 +5bx + 5ay-9ab=0` at P and Q, `anglePOQ=pi/2` then the relation between a and b is (A) `a=b` (B) `a=2b` or `b = 2a` (C) `a=3b` or `b = 3a` (D) `a + b = 5`

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