Two capacitors `C_1=1muF` and `C_2=3muF` each are charged to a potential difference of `100V` but with opposite polarity as shown in the figure. When the switch `S` is closed, the new potential difference between the points `a` and `b` is

Two capacitors C_(1) = 4 muF and C_(2) = 2muF are charged to same potential V = 500 Volt, but with opposite polarity as shown in the figure. The switches S_(1) and S_(2) are closed.

Two capacitors C_(1) and C_(2) are charged to same potential V , but with opposite polarity as shown in the figure. The switches S_(1) and S_(2) are then closed

Two capacitors C_(1) = 2mu F and C_(2) = 1 muF are charged to same potential V = 100 V , but with opposite polarity as shown in the figure. The switches S_(1) and S_(2) are closed. The ratio of final energy to the initial energy of the system is

In the arrangement shown in, When the switch S is closed, find . the final potential difference across the 12 muF capacitor.