x-y=2;4x+7y=30

Solve the following system of equations by matrix method : 5x+7y+2=0 4x+6y+3=0 5x+2y=3 3x+2y=5 3x+4y-5=0 x-y+3=0 3x+y=19 3x-y=23 3x+7y=4 x+2y=-1 3x+y=7 5x+3y=12

0.5x-7y=2 ; 3.4x-4.4y=15.4

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is 7x-y+23=0 7y+x+=30 7y+x=31 x-7y=30 x+7y+31=0

If [2x+y,4x,5x-7 4x]=[7 7y-13 y x+6] , then the value of x+y is x=3 , y=1 (b) x=2 , y=3 (c) x=2 , y=4 (d) x=3 , y=3

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is 7x-y+23=07y+x+=307y+x=31x-7y=30x+7y+31=0

The system of equations x+y+z=6, x+2y+3z=14, x+4y=7z=30 has

The circle x^2 + y^2+ 4x-7y + 12 = 0 cuts an intercept on y-axis equal to