The equations of two SHM's is given as `x = a cos (omega t + delta) and y = a cos (omega t + alpha)`, where `delta = alpha + (pi)/(2)` the resultant of the two SHM's represents

The equations of two waves given as x = a cos (omega t = delta) and y = a cos (omega t + alpha) , where delta = alpha + pi/2 , then resultant wave represent:

The equations of two waves given as x = a cos (omega t = delta) and y = a cos (omega t + alpha) , where delta = alpha + pi/2 , then resultant wave represent:

The equations of two waves acting in perpendicular direction are given as x = a cos (omega t + delta) " and " y = a cos (omega t + alpha) " where " delta = alpha + pi//2 the resultant wave represents

Two equations of two SHM y = a sin (omegat-alpha) and y = a cos (omegat-alpha) . The phase difference between the two is

Two simple harmonic motions act on a particle. These harmonic motions are x = A "cos"omegat + delta , y = A "cos"(omegat + alpha) when delta= alpha + (pi)/(2) , the resulting motion is

Two equations of two S.H.M. are y=alpha sin (omegat-alpha) and y=b cos ( omega t -alpha) . The phase difference between the two is

Two simple harmonic motions given by, x = a sin (omega t+delta) and y = a sin (omega t + delta + (pi)/(2)) act on a particle will be

Two simple harmonic motions given by, x = a sin (omega t+delta) and y = a sin (omega t + delta + (pi)/(2)) act on a particle will be

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude