If sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers, then k =

If the sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers, then k is equal to:

If the sum of first n even natural numbers is equal to k times the sum of first n odd natural number then k= a. 1/n b. (n-1)/n c. (n+1)/(2n) d. (n+1)/n

If the sum of first n even natural numbers is equal to k times the sum of first n odd natural number then k= 1/n b. (n-1)/n c. (n+1)/(2n) d. (n+1)/n

The sum of first n odd natural numbers is

If the sum of first n even natural numbers is equal to k xx the sum of first n odd natural number then k=(1)/(n) b.(n-1)/(n) c.(n+1)/(2n)d .(n+1)/(n)

The sum of first n odd natural number is

Find the sum of first n odd natural numbers.

Find the sum of first n odd natural numbers.

Write the sum of first n odd natural numbers.

Write the sum of first n odd natural numbers.