5a-[a^(2)-{2a(1-a+4a^(2))-3a(a^(2)-5a-3)}]-8

(5a^(3)-4a^(2)+3a+18)/(a^(2)-2a+3)

Simplify : a^(2) - 2a + {5a^(2) - 3a - 4a^(2)}

What must be added to the sum of 2a^(2)-3a+7,-5a^(2)-2a-11 and 3a^(2)+5a-8 to get 0?

Add the following -2a+5a^2-a^3+2, -5a^2 -2a^3 +4, a-a^2 +3a^3, -2a-3a^2-4, 6-3a+2a^2-2a^3

If the equation a^(2) x^(2) + (a^(2) - 5a + 4) xy + (3a - 2) y^(2) - 8x + 12y - 4 = 0 represents a circle , then : a =

Take away :(5a^(2))/(2)+(3a^(3))/(2)+(a)/(3)-(6)/(5) om (1)/(3)a^(3)-(3)/(4)a^(2)-(5)/(2)

Find the value of the expressions, when a= -1" and "b= 3 5a^(2)+4ab^(2)-8a^(2)b .

Add the following 5a+2a^2-3a^3+8, -4a^2 +5a^3 -9, -2a+6a^2 -3a^3 , -a+4a^2 -9, 4-a-2a^2 +3a^3

(2a^(2) + a - 1)/(a + 1) + (3a^(2) + 5a + 2)/(3a + 2) + (4 - a^(2))/(a+2) =..

2(4)/(5)-1(3)/(8)+3(1)/(2)=?