A particle is moving with a uniform acceleration `4 m s^(-2)` for time `2 second` and then `5 m s^(-20` for time `3 seconds`. What is the average acceleration of particle during motion.

A body moves along a straight line with acceleration 3m/s^2 for 2 seconds and then with acceleration 4 m/s^2 for 3 seconds . What is the average acceleration

A particle is moving with uniform acceleration. Its position (x) is given in terms of time (t in s) as X =(5t2+4t+8)m ,then

A particle describing a uniform accelerated motion, covers 118 m in the 5th second and 138 m in 10th second. Calculate the initial velocity and acceleration of the particle. What distance will be covered by the particle at the end of 20 s?

A particle starts moving with acceleration 2 m//s^(2) . Distance travelled by it in 5^(th) half second is

A particle starts moving with acceleration 2 m//s^(2) . Distance travelled by it in 5^(th) half second is

A particle moves in a straight line for 20 seconds with velocity 3 m/s and then moves with velocity 4 m/s for another 20 seconds and finally moves with velocity 5 m/s for next 20 seconds. What is the average velocity of the particle ?

A particle is initially at rest. It starts moving with a constant acceleration, the speed of the particle in t seconds is 50m/s and after one second the speed becomes 75m/s. calculate the acceleration of the particle and distance covered in (t+1)^("th") second of its motion.

A particle having initial velocity 5 m//s moves with a constant acceleration 2 m s^(-2) , for time 10 second along a straight line. Find the displacement of the particle in the last one second and the total distance traveled in 10 seconds .

A particle starts from rest with a time varying acceleration a=(2t-4) . Here t is in second and a in m//s^(2) The velocity time graph of the particle is